2(5c+1)-33=6c+5

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Solution for 2(5c+1)-33=6c+5 equation: 



2(5c+1)-33=6c+5

We move all terms to the left:

2(5c+1)-33-(6c+5)=0

We multiply parentheses

10c-(6c+5)+2-33=0

We get rid of parentheses

10c-6c-5+2-33=0

We add all the numbers together, and all the variables

4c-36=0

We move all terms containing c to the left, all other terms to the right

4c=36

c=36/4

c=9

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