2(5b-6)=2-4(3b-7)

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Solution for 2(5b-6)=2-4(3b-7) equation: 



2(5b-6)=2-4(3b-7)

We move all terms to the left:

2(5b-6)-(2-4(3b-7))=0

We multiply parentheses

10b-(2-4(3b-7))-12=0



We calculate terms in parentheses: -(2-4(3b-7)), so:

2-4(3b-7)

determiningTheFunctionDomain
-4(3b-7)+2

We multiply parentheses

-12b+28+2

We add all the numbers together, and all the variables

-12b+30

Back to the equation:

-(-12b+30)



We get rid of parentheses

10b+12b-30-12=0

We add all the numbers together, and all the variables

22b-42=0

We move all terms containing b to the left, all other terms to the right

22b=42

b=42/22

b=1+10/11

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