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2(5b+1)=2(1+4b)
We move all terms to the left:
2(5b+1)-(2(1+4b))=0
We add all the numbers together, and all the variables
2(5b+1)-(2(4b+1))=0
We multiply parentheses
10b-(2(4b+1))+2=0
We calculate terms in parentheses: -(2(4b+1)), so:We get rid of parentheses
2(4b+1)
We multiply parentheses
8b+2
Back to the equation:
-(8b+2)
10b-8b-2+2=0
We add all the numbers together, and all the variables
2b=0
b=0/2
b=0
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