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2(5-2x)=3(4x+1)
We move all terms to the left:
2(5-2x)-(3(4x+1))=0
We add all the numbers together, and all the variables
2(-2x+5)-(3(4x+1))=0
We multiply parentheses
-4x-(3(4x+1))+10=0
We calculate terms in parentheses: -(3(4x+1)), so:We get rid of parentheses
3(4x+1)
We multiply parentheses
12x+3
Back to the equation:
-(12x+3)
-4x-12x-3+10=0
We add all the numbers together, and all the variables
-16x+7=0
We move all terms containing x to the left, all other terms to the right
-16x=-7
x=-7/-16
x=7/16
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