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2(5+x2)+x=3
We move all terms to the left:
2(5+x2)+x-(3)=0
We add all the numbers together, and all the variables
2(+x^2+5)+x-3=0
We multiply parentheses
2x^2+x+10-3=0
We add all the numbers together, and all the variables
2x^2+x+7=0
a = 2; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·2·7
Δ = -55
Delta is less than zero, so there is no solution for the equation
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