2(5+r)-3=2(r+1)+5

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Solution for 2(5+r)-3=2(r+1)+5 equation: 


Simplifying
2(5 + r) + -3 = 2(r + 1) + 5
(5 * 2 + r * 2) + -3 = 2(r + 1) + 5
(10 + 2r) + -3 = 2(r + 1) + 5

Reorder the terms:
10 + -3 + 2r = 2(r + 1) + 5

Combine like terms: 10 + -3 = 7
7 + 2r = 2(r + 1) + 5

Reorder the terms:
7 + 2r = 2(1 + r) + 5
7 + 2r = (1 * 2 + r * 2) + 5
7 + 2r = (2 + 2r) + 5

Reorder the terms:
7 + 2r = 2 + 5 + 2r

Combine like terms: 2 + 5 = 7
7 + 2r = 7 + 2r

Add '-7' to each side of the equation.
7 + -7 + 2r = 7 + -7 + 2r

Combine like terms: 7 + -7 = 0
0 + 2r = 7 + -7 + 2r
2r = 7 + -7 + 2r

Combine like terms: 7 + -7 = 0
2r = 0 + 2r
2r = 2r

Add '-2r' to each side of the equation.
2r + -2r = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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