2(4z-6)=(3z-7)

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Solution for 2(4z-6)=(3z-7) equation: 



2(4z-6)=(3z-7)

We move all terms to the left:

2(4z-6)-((3z-7))=0

We multiply parentheses

8z-((3z-7))-12=0



We calculate terms in parentheses: -((3z-7)), so:

(3z-7)

We get rid of parentheses

3z-7

Back to the equation:

-(3z-7)



We get rid of parentheses

8z-3z+7-12=0

We add all the numbers together, and all the variables

5z-5=0

We move all terms containing z to the left, all other terms to the right

5z=5

z=5/5

z=1

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