2(4z-3)=7z-1

Solution for 2(4z-3)=7z-1 equation:

Simplifying
2(4z + -3) = 7z + -1

Reorder the terms:
2(-3 + 4z) = 7z + -1
(-3 * 2 + 4z * 2) = 7z + -1
(-6 + 8z) = 7z + -1

Reorder the terms:
-6 + 8z = -1 + 7z

Solving
-6 + 8z = -1 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-6 + 8z + -7z = -1 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-6 + 1z = -1 + 7z + -7z

Combine like terms: 7z + -7z = 0
-6 + 1z = -1 + 0
-6 + 1z = -1

Add '6' to each side of the equation.
-6 + 6 + 1z = -1 + 6

Combine like terms: -6 + 6 = 0
0 + 1z = -1 + 6
1z = -1 + 6

Combine like terms: -1 + 6 = 5
1z = 5

Divide each side by '1'.
z = 5

Simplifying
z = 5