2(4z-3)-(5z-6)=120-z

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Solution for 2(4z-3)-(5z-6)=120-z equation: 



2(4z-3)-(5z-6)=120-z

We move all terms to the left:

2(4z-3)-(5z-6)-(120-z)=0

We add all the numbers together, and all the variables

2(4z-3)-(5z-6)-(-1z+120)=0

We multiply parentheses

8z-(5z-6)-(-1z+120)-6=0

We get rid of parentheses

8z-5z+1z+6-120-6=0

We add all the numbers together, and all the variables

4z-120=0

We move all terms containing z to the left, all other terms to the right

4z=120

z=120/4

z=30

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