2(4z-1)=3(z+2)D=

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Solution for 2(4z-1)=3(z+2)D= equation: 



2(4z-1)=3(z+2)=

We move all terms to the left:

2(4z-1)-(3(z+2))=0

We multiply parentheses

8z-(3(z+2))-2=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

8z-3z-6-2=0

We add all the numbers together, and all the variables

5z-8=0

We move all terms containing z to the left, all other terms to the right

5z=8

z=8/5

z=1+3/5

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