2(4z-1)-6z=6-(z+2)

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Solution for 2(4z-1)-6z=6-(z+2) equation: 



2(4z-1)-6z=6-(z+2)

We move all terms to the left:

2(4z-1)-6z-(6-(z+2))=0

We add all the numbers together, and all the variables

-6z+2(4z-1)-(6-(z+2))=0

We multiply parentheses

-6z+8z-(6-(z+2))-2=0



We calculate terms in parentheses: -(6-(z+2)), so:

6-(z+2)

determiningTheFunctionDomain
-(z+2)+6

We get rid of parentheses

-z-2+6

We add all the numbers together, and all the variables

-1z+4

Back to the equation:

-(-1z+4)



We add all the numbers together, and all the variables

2z-(-1z+4)-2=0

We get rid of parentheses

2z+1z-4-2=0

We add all the numbers together, and all the variables

3z-6=0

We move all terms containing z to the left, all other terms to the right

3z=6

z=6/3

z=2

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