2(4z+5)=19-7z

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Solution for 2(4z+5)=19-7z equation: 



2(4z+5)=19-7z

We move all terms to the left:

2(4z+5)-(19-7z)=0

We add all the numbers together, and all the variables

2(4z+5)-(-7z+19)=0

We multiply parentheses

8z-(-7z+19)+10=0

We get rid of parentheses

8z+7z-19+10=0

We add all the numbers together, and all the variables

15z-9=0

We move all terms containing z to the left, all other terms to the right

15z=9

z=9/15

z=3/5

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