2(4y-1)-5=4(3y-2)

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Solution for 2(4y-1)-5=4(3y-2) equation: 



2(4y-1)-5=4(3y-2)

We move all terms to the left:

2(4y-1)-5-(4(3y-2))=0

We multiply parentheses

8y-(4(3y-2))-2-5=0



We calculate terms in parentheses: -(4(3y-2)), so:

4(3y-2)

We multiply parentheses

12y-8

Back to the equation:

-(12y-8)



We add all the numbers together, and all the variables

8y-(12y-8)-7=0

We get rid of parentheses

8y-12y+8-7=0

We add all the numbers together, and all the variables

-4y+1=0

We move all terms containing y to the left, all other terms to the right

-4y=-1

y=-1/-4

y=1/4

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