2(4y+2)=36

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Solution for 2(4y+2)=36 equation: 



2(4y+2)=36

We move all terms to the left:

2(4y+2)-(36)=0

We multiply parentheses

8y+4-36=0

We add all the numbers together, and all the variables

8y-32=0

We move all terms containing y to the left, all other terms to the right

8y=32

y=32/8

y=4

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