2(4y+2)=20

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Solution for 2(4y+2)=20 equation: 



2(4y+2)=20

We move all terms to the left:

2(4y+2)-(20)=0

We multiply parentheses

8y+4-20=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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