2(4y+10)=2(3y+3)

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Solution for 2(4y+10)=2(3y+3) equation: 



2(4y+10)=2(3y+3)

We move all terms to the left:

2(4y+10)-(2(3y+3))=0

We multiply parentheses

8y-(2(3y+3))+20=0



We calculate terms in parentheses: -(2(3y+3)), so:

2(3y+3)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

8y-6y-6+20=0

We add all the numbers together, and all the variables

2y+14=0

We move all terms containing y to the left, all other terms to the right

2y=-14

y=-14/2

y=-7

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