2(4y+1)=-(4y+10)

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Solution for 2(4y+1)=-(4y+10) equation: 



2(4y+1)=-(4y+10)

We move all terms to the left:

2(4y+1)-(-(4y+10))=0

We multiply parentheses

8y-(-(4y+10))+2=0



We calculate terms in parentheses: -(-(4y+10)), so:

-(4y+10)

We get rid of parentheses

-4y-10

Back to the equation:

-(-4y-10)



We get rid of parentheses

8y+4y+10+2=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1

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