2(4xy+5)(4xy-5)=

Solution for 2(4xy+5)(4xy-5)= equation:

Simplifying
2(4xy + 5)(4xy + -5) = 0

Reorder the terms:
2(5 + 4xy)(4xy + -5) = 0

Reorder the terms:
2(5 + 4xy)(-5 + 4xy) = 0

Multiply (5 + 4xy) * (-5 + 4xy)
2(5(-5 + 4xy) + 4xy * (-5 + 4xy)) = 0
2((-5 * 5 + 4xy * 5) + 4xy * (-5 + 4xy)) = 0
2((-25 + 20xy) + 4xy * (-5 + 4xy)) = 0
2(-25 + 20xy + (-5 * 4xy + 4xy * 4xy)) = 0
2(-25 + 20xy + (-20xy + 16x2y2)) = 0

Combine like terms: 20xy + -20xy = 0
2(-25 + 0 + 16x2y2) = 0
2(-25 + 16x2y2) = 0
(-25 * 2 + 16x2y2 * 2) = 0
(-50 + 32x2y2) = 0

Solving
-50 + 32x2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 32x2y2 = 0 + 50

Combine like terms: -50 + 50 = 0
0 + 32x2y2 = 0 + 50
32x2y2 = 0 + 50

Combine like terms: 0 + 50 = 50
32x2y2 = 50

Divide each side by '32y2'.
x2 = 1.5625y-2

Simplifying
x2 = 1.5625y-2

Take the square root of each side:
x = {-1.25y-1, 1.25y-1}