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2(4x-5)=2x+2(3x-5)
We move all terms to the left:
2(4x-5)-(2x+2(3x-5))=0
We multiply parentheses
8x-(2x+2(3x-5))-10=0
We calculate terms in parentheses: -(2x+2(3x-5)), so:We get rid of parentheses
2x+2(3x-5)
We multiply parentheses
2x+6x-10
We add all the numbers together, and all the variables
8x-10
Back to the equation:
-(8x-10)
8x-8x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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