2(4x-5)-3=-4(x+2)+1

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Solution for 2(4x-5)-3=-4(x+2)+1 equation: 



2(4x-5)-3=-4(x+2)+1

We move all terms to the left:

2(4x-5)-3-(-4(x+2)+1)=0

We multiply parentheses

8x-(-4(x+2)+1)-10-3=0



We calculate terms in parentheses: -(-4(x+2)+1), so:

-4(x+2)+1

We multiply parentheses

-4x-8+1

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We add all the numbers together, and all the variables

8x-(-4x-7)-13=0

We get rid of parentheses

8x+4x+7-13=0

We add all the numbers together, and all the variables

12x-6=0

We move all terms containing x to the left, all other terms to the right

12x=6

x=6/12

x=1/2

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