2(4x-4)+3x=(20x-10)/2

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Solution for 2(4x-4)+3x=(20x-10)/2 equation:



2(4x-4)+3x=(20x-10)/2
We move all terms to the left:
2(4x-4)+3x-((20x-10)/2)=0
We add all the numbers together, and all the variables
3x+2(4x-4)-((20x-10)/2)=0
We multiply parentheses
3x+8x-((20x-10)/2)-8=0
We multiply all the terms by the denominator
3x*2)+8x*2)-((20x-10)-8*2)=0
We add all the numbers together, and all the variables
3x*2)+8x*2)-((20x=0
Wy multiply elements
12x^3=0
We do not support expression: x^3

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