2(4x-4)+2=4(x+1)+6

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Solution for 2(4x-4)+2=4(x+1)+6 equation: 



2(4x-4)+2=4(x+1)+6

We move all terms to the left:

2(4x-4)+2-(4(x+1)+6)=0

We multiply parentheses

8x-(4(x+1)+6)-8+2=0



We calculate terms in parentheses: -(4(x+1)+6), so:

4(x+1)+6

We multiply parentheses

4x+4+6

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We add all the numbers together, and all the variables

8x-(4x+10)-6=0

We get rid of parentheses

8x-4x-10-6=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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