2(4x-3)=7(x+1)

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Solution for 2(4x-3)=7(x+1) equation: 



2(4x-3)=7(x+1)

We move all terms to the left:

2(4x-3)-(7(x+1))=0

We multiply parentheses

8x-(7(x+1))-6=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

8x-7x-7-6=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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