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2(4x+5)+4=3(x-10)-6
We move all terms to the left:
2(4x+5)+4-(3(x-10)-6)=0
We multiply parentheses
8x-(3(x-10)-6)+10+4=0
We calculate terms in parentheses: -(3(x-10)-6), so:We add all the numbers together, and all the variables
3(x-10)-6
We multiply parentheses
3x-30-6
We add all the numbers together, and all the variables
3x-36
Back to the equation:
-(3x-36)
8x-(3x-36)+14=0
We get rid of parentheses
8x-3x+36+14=0
We add all the numbers together, and all the variables
5x+50=0
We move all terms containing x to the left, all other terms to the right
5x=-50
x=-50/5
x=-10
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