2(4x+3)+12=34-x

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Solution for 2(4x+3)+12=34-x equation: 



2(4x+3)+12=34-x

We move all terms to the left:

2(4x+3)+12-(34-x)=0

We add all the numbers together, and all the variables

2(4x+3)-(-1x+34)+12=0

We multiply parentheses

8x-(-1x+34)+6+12=0

We get rid of parentheses

8x+1x-34+6+12=0

We add all the numbers together, and all the variables

9x-16=0

We move all terms containing x to the left, all other terms to the right

9x=16

x=16/9

x=1+7/9

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