2(4x+12-x)=4(1-x+10)

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Solution for 2(4x+12-x)=4(1-x+10) equation: 



2(4x+12-x)=4(1-x+10)

We move all terms to the left:

2(4x+12-x)-(4(1-x+10))=0

We add all the numbers together, and all the variables

2(3x+12)-(4(-1x+11))=0

We multiply parentheses

6x-(4(-1x+11))+24=0



We calculate terms in parentheses: -(4(-1x+11)), so:

4(-1x+11)

We multiply parentheses

-4x+44

Back to the equation:

-(-4x+44)



We get rid of parentheses

6x+4x-44+24=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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