2(4x+1)=80

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Solution for 2(4x+1)=80 equation: 



2(4x+1)=80

We move all terms to the left:

2(4x+1)-(80)=0

We multiply parentheses

8x+2-80=0

We add all the numbers together, and all the variables

8x-78=0

We move all terms containing x to the left, all other terms to the right

8x=78

x=78/8

x=9+3/4

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