2(4x+1)+2x=10-2(x-2)

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Solution for 2(4x+1)+2x=10-2(x-2) equation: 



2(4x+1)+2x=10-2(x-2)

We move all terms to the left:

2(4x+1)+2x-(10-2(x-2))=0

We add all the numbers together, and all the variables

2x+2(4x+1)-(10-2(x-2))=0

We multiply parentheses

2x+8x-(10-2(x-2))+2=0



We calculate terms in parentheses: -(10-2(x-2)), so:

10-2(x-2)

determiningTheFunctionDomain
-2(x-2)+10

We multiply parentheses

-2x+4+10

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We add all the numbers together, and all the variables

10x-(-2x+14)+2=0

We get rid of parentheses

10x+2x-14+2=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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