2(4t-5)=6(2t+3)-5

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Solution for 2(4t-5)=6(2t+3)-5 equation: 



2(4t-5)=6(2t+3)-5

We move all terms to the left:

2(4t-5)-(6(2t+3)-5)=0

We multiply parentheses

8t-(6(2t+3)-5)-10=0



We calculate terms in parentheses: -(6(2t+3)-5), so:

6(2t+3)-5

We multiply parentheses

12t+18-5

We add all the numbers together, and all the variables

12t+13

Back to the equation:

-(12t+13)



We get rid of parentheses

8t-12t-13-10=0

We add all the numbers together, and all the variables

-4t-23=0

We move all terms containing t to the left, all other terms to the right

-4t=23

t=23/-4

t=-5+3/4

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