2(4t-5)=21t+6

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Solution for 2(4t-5)=21t+6 equation: 



2(4t-5)=21t+6

We move all terms to the left:

2(4t-5)-(21t+6)=0

We multiply parentheses

8t-(21t+6)-10=0

We get rid of parentheses

8t-21t-6-10=0

We add all the numbers together, and all the variables

-13t-16=0

We move all terms containing t to the left, all other terms to the right

-13t=16

t=16/-13

t=-1+3/13

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