2(4t-3)-8=4+2t

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Solution for 2(4t-3)-8=4+2t equation: 



2(4t-3)-8=4+2t

We move all terms to the left:

2(4t-3)-8-(4+2t)=0

We add all the numbers together, and all the variables

2(4t-3)-(2t+4)-8=0

We multiply parentheses

8t-(2t+4)-6-8=0

We get rid of parentheses

8t-2t-4-6-8=0

We add all the numbers together, and all the variables

6t-18=0

We move all terms containing t to the left, all other terms to the right

6t=18

t=18/6

t=3

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