2(4r-4)=-10+7r

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Solution for 2(4r-4)=-10+7r equation: 



2(4r-4)=-10+7r

We move all terms to the left:

2(4r-4)-(-10+7r)=0

We add all the numbers together, and all the variables

2(4r-4)-(7r-10)=0

We multiply parentheses

8r-(7r-10)-8=0

We get rid of parentheses

8r-7r+10-8=0

We add all the numbers together, and all the variables

r+2=0

We move all terms containing r to the left, all other terms to the right

r=-2

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