2(4n-3)=7(n-9)+4n

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Solution for 2(4n-3)=7(n-9)+4n equation: 



2(4n-3)=7(n-9)+4n

We move all terms to the left:

2(4n-3)-(7(n-9)+4n)=0

We multiply parentheses

8n-(7(n-9)+4n)-6=0



We calculate terms in parentheses: -(7(n-9)+4n), so:

7(n-9)+4n

We add all the numbers together, and all the variables

4n+7(n-9)

We multiply parentheses

4n+7n-63

We add all the numbers together, and all the variables

11n-63

Back to the equation:

-(11n-63)



We get rid of parentheses

8n-11n+63-6=0

We add all the numbers together, and all the variables

-3n+57=0

We move all terms containing n to the left, all other terms to the right

-3n=-57

n=-57/-3

n=+19

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