2(4n)+4n-20+33n=2

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Solution for 2(4n)+4n-20+33n=2 equation: 



2(4n)+4n-20+33n=2

We move all terms to the left:

2(4n)+4n-20+33n-(2)=0

We add all the numbers together, and all the variables

61n-22=0

We move all terms containing n to the left, all other terms to the right

61n=22

n=22/61

n=22/61

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