2(4m-5)-(6m+11)=33+m

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Solution for 2(4m-5)-(6m+11)=33+m equation: 



2(4m-5)-(6m+11)=33+m

We move all terms to the left:

2(4m-5)-(6m+11)-(33+m)=0

We add all the numbers together, and all the variables

2(4m-5)-(6m+11)-(m+33)=0

We multiply parentheses

8m-(6m+11)-(m+33)-10=0

We get rid of parentheses

8m-6m-m-11-33-10=0

We add all the numbers together, and all the variables

m-54=0

We move all terms containing m to the left, all other terms to the right

m=54

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