2(4m+3)=15+5m

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Solution for 2(4m+3)=15+5m equation: 



2(4m+3)=15+5m

We move all terms to the left:

2(4m+3)-(15+5m)=0

We add all the numbers together, and all the variables

2(4m+3)-(5m+15)=0

We multiply parentheses

8m-(5m+15)+6=0

We get rid of parentheses

8m-5m-15+6=0

We add all the numbers together, and all the variables

3m-9=0

We move all terms containing m to the left, all other terms to the right

3m=9

m=9/3

m=3

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