2(4m+2)=4m-12(m-1)

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Solution for 2(4m+2)=4m-12(m-1) equation: 



2(4m+2)=4m-12(m-1)

We move all terms to the left:

2(4m+2)-(4m-12(m-1))=0

We multiply parentheses

8m-(4m-12(m-1))+4=0



We calculate terms in parentheses: -(4m-12(m-1)), so:

4m-12(m-1)

We multiply parentheses

4m-12m+12

We add all the numbers together, and all the variables

-8m+12

Back to the equation:

-(-8m+12)



We get rid of parentheses

8m+8m-12+4=0

We add all the numbers together, and all the variables

16m-8=0

We move all terms containing m to the left, all other terms to the right

16m=8

m=8/16

m=1/2

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