2(4k-1)=5(k-1)

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Solution for 2(4k-1)=5(k-1) equation: 



2(4k-1)=5(k-1)

We move all terms to the left:

2(4k-1)-(5(k-1))=0

We multiply parentheses

8k-(5(k-1))-2=0



We calculate terms in parentheses: -(5(k-1)), so:

5(k-1)

We multiply parentheses

5k-5

Back to the equation:

-(5k-5)



We get rid of parentheses

8k-5k+5-2=0

We add all the numbers together, and all the variables

3k+3=0

We move all terms containing k to the left, all other terms to the right

3k=-3

k=-3/3

k=-1

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