2(4f+3)=3(2f+6)

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Solution for 2(4f+3)=3(2f+6) equation: 



2(4f+3)=3(2f+6)

We move all terms to the left:

2(4f+3)-(3(2f+6))=0

We multiply parentheses

8f-(3(2f+6))+6=0



We calculate terms in parentheses: -(3(2f+6)), so:

3(2f+6)

We multiply parentheses

6f+18

Back to the equation:

-(6f+18)



We get rid of parentheses

8f-6f-18+6=0

We add all the numbers together, and all the variables

2f-12=0

We move all terms containing f to the left, all other terms to the right

2f=12

f=12/2

f=6

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