2(4c-11)=3(c+10)+8

Solution for 2(4c-11)=3(c+10)+8 equation:

2(4c-11)=3(c+10)+8

We move all terms to the left:

2(4c-11)-(3(c+10)+8)=0

We multiply parentheses

8c-(3(c+10)+8)-22=0


We calculate terms in parentheses: -(3(c+10)+8), so:

3(c+10)+8

We multiply parentheses

3c+30+8

We add all the numbers together, and all the variables

3c+38

Back to the equation:

-(3c+38)


We get rid of parentheses

8c-3c-38-22=0

We add all the numbers together, and all the variables

5c-60=0

We move all terms containing c to the left, all other terms to the right

5c=60

c=60/5

c=12