2(4c+1)+7(c+)=-32

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Solution for 2(4c+1)+7(c+)=-32 equation: 



2(4c+1)+7(c+)=-32

We move all terms to the left:

2(4c+1)+7(c+)-(-32)=0

We add all the numbers together, and all the variables

2(4c+1)+7c-(-32)=0

We add all the numbers together, and all the variables

7c+2(4c+1)+32=0

We multiply parentheses

7c+8c+2+32=0

We add all the numbers together, and all the variables

15c+34=0

We move all terms containing c to the left, all other terms to the right

15c=-34

c=-34/15

c=-2+4/15

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