2(4b-6)=12b-28

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Solution for 2(4b-6)=12b-28 equation: 



2(4b-6)=12b-28

We move all terms to the left:

2(4b-6)-(12b-28)=0

We multiply parentheses

8b-(12b-28)-12=0

We get rid of parentheses

8b-12b+28-12=0

We add all the numbers together, and all the variables

-4b+16=0

We move all terms containing b to the left, all other terms to the right

-4b=-16

b=-16/-4

b=+4

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