2(4b-3)-8=4+2b

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Solution for 2(4b-3)-8=4+2b equation: 



2(4b-3)-8=4+2b

We move all terms to the left:

2(4b-3)-8-(4+2b)=0

We add all the numbers together, and all the variables

2(4b-3)-(2b+4)-8=0

We multiply parentheses

8b-(2b+4)-6-8=0

We get rid of parentheses

8b-2b-4-6-8=0

We add all the numbers together, and all the variables

6b-18=0

We move all terms containing b to the left, all other terms to the right

6b=18

b=18/6

b=3

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