2(4a+3)+6(a+1)=54

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Solution for 2(4a+3)+6(a+1)=54 equation: 



2(4a+3)+6(a+1)=54

We move all terms to the left:

2(4a+3)+6(a+1)-(54)=0

We multiply parentheses

8a+6a+6+6-54=0

We add all the numbers together, and all the variables

14a-42=0

We move all terms containing a to the left, all other terms to the right

14a=42

a=42/14

a=3

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