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2(4a+2)=+5(5+2a)
We move all terms to the left:
2(4a+2)-(+5(5+2a))=0
We add all the numbers together, and all the variables
2(4a+2)-(+5(2a+5))=0
We multiply parentheses
8a-(+5(2a+5))+4=0
We calculate terms in parentheses: -(+5(2a+5)), so:We get rid of parentheses
+5(2a+5)
determiningTheFunctionDomain 5(2a+5)
We multiply parentheses
10a+25
Back to the equation:
-(10a+25)
8a-10a-25+4=0
We add all the numbers together, and all the variables
-2a-21=0
We move all terms containing a to the left, all other terms to the right
-2a=21
a=21/-2
a=-10+1/2
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