2(41-y)+4y=106

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Solution for 2(41-y)+4y=106 equation: 



2(41-y)+4y=106

We move all terms to the left:

2(41-y)+4y-(106)=0

We add all the numbers together, and all the variables

2(-1y+41)+4y-106=0

We add all the numbers together, and all the variables

4y+2(-1y+41)-106=0

We multiply parentheses

4y-2y+82-106=0

We add all the numbers together, and all the variables

2y-24=0

We move all terms containing y to the left, all other terms to the right

2y=24

y=24/2

y=12

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