2(40-y)+4y=106

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Solution for 2(40-y)+4y=106 equation: 



2(40-y)+4y=106

We move all terms to the left:

2(40-y)+4y-(106)=0

We add all the numbers together, and all the variables

2(-1y+40)+4y-106=0

We add all the numbers together, and all the variables

4y+2(-1y+40)-106=0

We multiply parentheses

4y-2y+80-106=0

We add all the numbers together, and all the variables

2y-26=0

We move all terms containing y to the left, all other terms to the right

2y=26

y=26/2

y=13

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