2(40-5y)=10y+5(1-y)

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Solution for 2(40-5y)=10y+5(1-y) equation: 



2(40-5y)=10y+5(1-y)

We move all terms to the left:

2(40-5y)-(10y+5(1-y))=0

We add all the numbers together, and all the variables

2(-5y+40)-(10y+5(-1y+1))=0

We multiply parentheses

-10y-(10y+5(-1y+1))+80=0



We calculate terms in parentheses: -(10y+5(-1y+1)), so:

10y+5(-1y+1)

We multiply parentheses

10y-5y+5

We add all the numbers together, and all the variables

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

-10y-5y-5+80=0

We add all the numbers together, and all the variables

-15y+75=0

We move all terms containing y to the left, all other terms to the right

-15y=-75

y=-75/-15

y=+5

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