2(40-5y)=10y+5(1-y

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Solution for 2(40-5y)=10y+5(1-y equation:



2(40-5y)=10y+5(1-y
We move all terms to the left:
2(40-5y)-(10y+5(1-y)=0
We add all the numbers together, and all the variables
2(-5y+40)-(10y+5(-1y+1)=0
We multiply parentheses
-10y-(10y+5(-1y+1)+80=0

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