2(4-x)=6(x+4)+4x

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Solution for 2(4-x)=6(x+4)+4x equation: 



2(4-x)=6(x+4)+4x

We move all terms to the left:

2(4-x)-(6(x+4)+4x)=0

We add all the numbers together, and all the variables

2(-1x+4)-(6(x+4)+4x)=0

We multiply parentheses

-2x-(6(x+4)+4x)+8=0



We calculate terms in parentheses: -(6(x+4)+4x), so:

6(x+4)+4x

We add all the numbers together, and all the variables

4x+6(x+4)

We multiply parentheses

4x+6x+24

We add all the numbers together, and all the variables

10x+24

Back to the equation:

-(10x+24)



We get rid of parentheses

-2x-10x-24+8=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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